On Monday, 11 January 2021 at 16:56:05 UTC, ag0aep6g wrote:
On Monday, 11 January 2021 at 16:40:01 UTC, Jack wrote:
let's say a I have this:
void f(X foo) { }
but I'd like to make f() accept immutable X too so instead of
cast away everywhere in the code where immutable(X) is passed
to f() or make a overload for this, are there any way to
accept both in same function? those function are callback-like
functions, I have lots of them so already and would need to
double, if I do add an overload just for the immutable. I did
come up with something using templates, not sure if it's ugly:
void f(T)(T x)
if(is(T == C) || is(T == immutable(C)) {
// ...
}
Accepting both mutable and immutable is what `const` is for:
void f(const X foo) { ... }
thanks! now, how would I add const here?
import std.container : SList;
auto l = SList!Callabck();
doesn't work:
auto l = SList!(const(Callabck()));
auto l = SList!(const Callabck());
