I believe that pt1(r) value is created on the stack, then the thefunc is
called with that value (by Value semantic - so another value is created
on the stack) and it prints pointer to the value on the stack. Then it
returnes so the stack values are destroyed, next iteration begins and
all steps are the same. The addresses of the values are just the same as
thay were in previous loop. calling the function is deterministic so the
addresses are also because nothing else stays on the stack between two
iterations.
On 23.12.2010 00:16, g g wrote:
Is this code :
import std.stdio;
import std.conv;
struct pt1{
p val;
pt1* next;
}
struct p{
int val;
string toString(){
return(to!string(val));
}
}
void thefun(pt1 x){
writeln(&x);
}
void main(){
auto p0 = p(1);
auto p1 = p(2);
auto p2 = p(3);
auto p3 = p(4);
p[] arr = [p0,p1,p2,p3];
writeln(arr);
foreach(r;arr){
thefun(pt1(r));
}
}
supposed to output this:
1 2 3 4
BFE61E28
BFE61E28
BFE61E28
BFE61E28 //Note all the addresses are the same
It is expected that using a struct literal(or default constructor) on a bucle
reuses the same address?
I got hit by this trying to do a tree structure builder, for hours searching
aand finally found this (feature | bug). If so, how I could get a new struct to
void changing (in a unnoticeable way) the same struct i just set.
thanks.
g g
