On 12/10/2010 21:25, Bob Cowdery wrote: > On 12/10/2010 21:11, Simen kjaeraas wrote: >> Bob Cowdery <b...@bobcowdery.plus.com> wrote: >> >>> On 12/10/2010 20:29, Simen kjaeraas wrote: >>>> Bob Cowdery <b...@bobcowdery.plus.com> wrote: >>>> >>>>> x_points[] >>>>> =(x_average[0]+x_average[1]+x_average[2]+x_average[3]+x_average[4]+x_average[5]+ >>>>> >>>>> >>>>> x_average[6]+x_average[7]+x_average[8]+x_average[9])/10; >>>>> >>>>> The average gives me a compile error of incompatible types. >>>> You need to append [] to x_average[index]. >>>> >>>> >>> Thanks. I tried it the other way round [][0]. To put [0][] seems to me >>> the wrong way round. Probably just not understanding the syntax >>> properly. >> Yeah, it's a bit the wrong way around, for those coming from C, at least. >> The idea is that for any T[] t, t[0] should behave as if a function >> returning a T. So, for char[][] c, c[0] returns char[], which would then >> be indexed by the next brackets. If index was the function: >> >> c[0][1] => index( index( c, 0 ), 1 ); >> >> > Ok, kind of understand that. Now I have another problem. > > x_average[ptr] = x_points; // tells me array length don't match. > > When I print x_average[ptr] or x_average[][ptr] or x_average[ptr][] they > all tell me the length is 10. What do I have to do to get to the row > which is 600? > Got it now. The array was defined back to front as well. Should have been
x_average[10][600] (I think, seems to work anyway).
