What did you mean with "*in some parent object and call the function from
within the webview*"?
Solution below did not do the trick - link is still opened in the same
webview...
Item
{
id: htmlContentViewer
WebView {
id: webViewer
anchors.fill: parent
onNavigationRequested : {
console.debug("request.url: ", request.url)
if (request.navigationType === WebView.LinkClickedNavigation) {
request.action = WebView.IgnoreRequest
//Qt.openUrlExternally(request.url)
goExternal(request.url)
}
}
}
// fancy Sailfish - WebView? - issue...
function goExternal( url ) { Qt.openUrlExternally(url) }
}
2016-01-28 22:21 GMT+01:00 Michael Fuchs <mic...@gmx.at>:
> Place the Qt.openUrlExternally(request.url) in a function in some parent
> object and call the function from within the webview.
>
> On Donnerstag, 28. Jänner 2016 21:55:49 CET Zoltán Lutor wrote:
> > Hi,
> >
> > Any idea how to open link clicked in webview in browser application?
> > Code below does not do the trick - rather opens link inside the webview
> > itself...
> >
> >
> http://doc.qt.io/qt-5/qml-qtwebkit-webview.html#onNavigationRequested-signal
> >
> > WebView {
> >
> > id: webViewer
> >
> > anchors.fill: parent
> >
> > onNavigationRequested : {
> >
> > console.debug("request.url: ", request.url)
> >
> > if (request.navigationType ===
> WebView.LinkClickedNavigation) {
> >
> > request.action = WebView.IgnoreRequest
> >
> > Qt.openUrlExternally(request.url)
> >
> > }
> >
> > }
> >
> > }
> >
> >
> > Thx,
> >
> >
> > Zoltan
>
>
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