Przemek Klosowski via devel wrote:
> so for one module with two versions, we will have 2 builds, for 2
> modules with two versions we'll have four builds, and in general for N
> modules with M versions on average, we will have N^M builds?

M^N actually.

1 module with M versions = M builds
2 modules with M versions each = M*M=M^2 builds
3 modules with M versions each = M*M*M=M^3 builds
…
n modules with M versions each = M^N builds

> This is a textbook combinatorial explosion:  100 modules with average 3
> versions each is a million builds and tests

It is actually 3^100 > 5*10^47 builds. That's more than
500 000 000 000 000 000 000 000 000 000 000 000 000 000 million builds, not 
1 million.

        Kevin Kofler
_______________________________________________
devel mailing list -- devel@lists.fedoraproject.org
To unsubscribe send an email to devel-le...@lists.fedoraproject.org
Fedora Code of Conduct: 
https://docs.fedoraproject.org/en-US/project/code-of-conduct/
List Guidelines: https://fedoraproject.org/wiki/Mailing_list_guidelines
List Archives: 
https://lists.fedoraproject.org/archives/list/devel@lists.fedoraproject.org

Reply via email to