REF: https://bugzilla.tianocore.org/show_bug.cgi?id=1964
If the file begin with single line Feed ('\n'), then "AsciiChar == '\n' && ((CHAR8*)Buffer)[LoopVar-1] != '\r'" would cause a underflow. Add this condition "(AsciiChar == '\n' && LoopVar == 0)" before it to make sure (LoopVar - 1) would never encounter a underflow. Cc: Jaben Carsey <jaben.car...@intel.com> Cc: Ray Ni <ray...@intel.com> Cc: Andrew Fish <af...@apple.com> Signed-off-by: Zhichao Gao <zhichao....@intel.com> --- ShellPkg/Library/UefiShellLevel3CommandsLib/Type.c | 11 ++++++----- 1 file changed, 6 insertions(+), 5 deletions(-) diff --git a/ShellPkg/Library/UefiShellLevel3CommandsLib/Type.c b/ShellPkg/Library/UefiShellLevel3CommandsLib/Type.c index 4efc0a8e24..c1f670c713 100644 --- a/ShellPkg/Library/UefiShellLevel3CommandsLib/Type.c +++ b/ShellPkg/Library/UefiShellLevel3CommandsLib/Type.c @@ -78,12 +78,13 @@ TypeFileByHandle ( // Allow Line Feed (LF) (0xA) & Carriage Return (CR) (0xD) // characters to be displayed as is. // - if (AsciiChar == '\n' && ((CHAR8*)Buffer)[LoopVar-1] != '\r') { + if ((AsciiChar == '\n' && LoopVar == 0) || + (AsciiChar == '\n' && ((CHAR8*)Buffer)[LoopVar-1] != '\r')) { // - // In case Line Feed (0xA) is encountered & Carriage Return (0xD) - // was not the previous character, print CR and LF. This is because - // Shell 2.0 requires carriage return with line feed for displaying - // each new line from left. + // In case file begin with single line Feed or Line Feed (0xA) is + // encountered & Carriage Return (0xD) was not previous character, + // print CR and LF. This is because Shell 2.0 requires carriage + // return Swith line feed for displaying each new line from left. // ShellPrintEx (-1, -1, L"\r\n"); continue; -- 2.21.0.windows.1 -=-=-=-=-=-=-=-=-=-=-=- Groups.io Links: You receive all messages sent to this group. View/Reply Online (#43711): https://edk2.groups.io/g/devel/message/43711 Mute This Topic: https://groups.io/mt/32476115/21656 Group Owner: devel+ow...@edk2.groups.io Unsubscribe: https://edk2.groups.io/g/devel/unsub [arch...@mail-archive.com] -=-=-=-=-=-=-=-=-=-=-=-