what i am trying to say is: structured data != sql

On Mon, Jan 26, 2015 at 7:26 PM, Koert Kuipers <ko...@tresata.com> wrote:

> "The context is that SchemaRDD is becoming a common data format used for
> bringing data into Spark from external systems, and used for various
> components of Spark, e.g. MLlib's new pipeline API."
>
> i agree. this to me also implies it belongs in spark core, not sql
>
> On Mon, Jan 26, 2015 at 6:11 PM, Michael Malak <
> michaelma...@yahoo.com.invalid> wrote:
>
>> And in the off chance that anyone hasn't seen it yet, the Jan. 13 Bay
>> Area Spark Meetup YouTube contained a wealth of background information on
>> this idea (mostly from Patrick and Reynold :-).
>>
>> https://www.youtube.com/watch?v=YWppYPWznSQ
>>
>> ________________________________
>> From: Patrick Wendell <pwend...@gmail.com>
>> To: Reynold Xin <r...@databricks.com>
>> Cc: "dev@spark.apache.org" <dev@spark.apache.org>
>> Sent: Monday, January 26, 2015 4:01 PM
>> Subject: Re: renaming SchemaRDD -> DataFrame
>>
>>
>> One thing potentially not clear from this e-mail, there will be a 1:1
>> correspondence where you can get an RDD to/from a DataFrame.
>>
>>
>> On Mon, Jan 26, 2015 at 2:18 PM, Reynold Xin <r...@databricks.com> wrote:
>> > Hi,
>> >
>> > We are considering renaming SchemaRDD -> DataFrame in 1.3, and wanted to
>> > get the community's opinion.
>> >
>> > The context is that SchemaRDD is becoming a common data format used for
>> > bringing data into Spark from external systems, and used for various
>> > components of Spark, e.g. MLlib's new pipeline API. We also expect more
>> and
>> > more users to be programming directly against SchemaRDD API rather than
>> the
>> > core RDD API. SchemaRDD, through its less commonly used DSL originally
>> > designed for writing test cases, always has the data-frame like API. In
>> > 1.3, we are redesigning the API to make the API usable for end users.
>> >
>> >
>> > There are two motivations for the renaming:
>> >
>> > 1. DataFrame seems to be a more self-evident name than SchemaRDD.
>> >
>> > 2. SchemaRDD/DataFrame is actually not going to be an RDD anymore (even
>> > though it would contain some RDD functions like map, flatMap, etc), and
>> > calling it Schema*RDD* while it is not an RDD is highly confusing.
>> Instead.
>> > DataFrame.rdd will return the underlying RDD for all RDD methods.
>> >
>> >
>> > My understanding is that very few users program directly against the
>> > SchemaRDD API at the moment, because they are not well documented.
>> However,
>> > oo maintain backward compatibility, we can create a type alias DataFrame
>> > that is still named SchemaRDD. This will maintain source compatibility
>> for
>> > Scala. That said, we will have to update all existing materials to use
>> > DataFrame rather than SchemaRDD.
>>
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>

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