There is no external users for ofpbuf_use() directly.
Signed-off-by: Andy Zhou <az...@nicira.com>
---
lib/ofpbuf.c | 2 +-
lib/ofpbuf.h | 1 -
2 files changed, 1 insertion(+), 2 deletions(-)
diff --git a/lib/ofpbuf.c b/lib/ofpbuf.c
index 392f843..c190f8b 100644
--- a/lib/ofpbuf.c
+++ b/lib/ofpbuf.c
@@ -47,7 +47,7 @@ ofpbuf_use__(struct ofpbuf *b, void *base, size_t allocated,
size_t size,
* memory starting at 'base'. 'base' should be the first byte of a region
* obtained from malloc(). It will be freed (with free()) if 'b' is resized or
* freed. */
-void
+static void
ofpbuf_use(struct ofpbuf *b, void *base, size_t allocated)
{
ofpbuf_use__(b, base, allocated, 0, OFPBUF_MALLOC);
diff --git a/lib/ofpbuf.h b/lib/ofpbuf.h
index 17257a0..873065e 100644
--- a/lib/ofpbuf.h
+++ b/lib/ofpbuf.h
@@ -83,7 +83,6 @@ struct ofpbuf {
.source = OFPBUF_STUB, \
}
-void ofpbuf_use(struct ofpbuf *, void *, size_t);
void ofpbuf_use_ds(struct ofpbuf *, const struct ds *);
void ofpbuf_use_stack(struct ofpbuf *, void *, size_t);
void ofpbuf_use_stub(struct ofpbuf *, void *, size_t);
--
1.9.1
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