Hum.. ok.
Running "git grep lowsetup" I just found it on UART peripheral code.
And in the case of ESP32, for example, although there is a comment
mentioning "esp32_lowsetup()"
it was not actually implemented.

Em qui., 11 de mar. de 2021 às 13:13, Gregory Nutt <spudan...@gmail.com>
escreveu:

> No, xyz_earlyearlyinit() initializes the serial driver to support a
> serial console device (stdin, stdout, stderr).  xyz_lowsetup() may
> initialize any hardware, not necessarily UART.  It has nothing to do
> with the serial driver. It initializes whatever hardware in necessary to
> start the system.  That normally includes the hardware UART that will be
> used later for the console.
>
> On 3/11/2021 8:59 AM, Sara da Cunha Monteiro de Souza wrote:
> > Hi Mr Nutt,
> >
> > I am so sorry for delaying my answer.
> > I went into vacation and missed this conversation.
> >
> > So, I came up to the conclusion that the *<chip>_lowsetup *function that
> > I've seen in many chips
> > is a standard deviation and it is actually playing the role of the
> > *xyz_earlyserialinit().*
> > Am I right?
> >
> > Thanks too much for the detailed explanation.
> >
> > Em qua., 10 de fev. de 2021 às 12:33, Gregory Nutt <spudan...@gmail.com>
> > escreveu:
> >
> >> As I said, the early serial initialization is needed for boot-up debug
> >> output.  Here is a little more detail:
> >>
> >> If the serial is not initialized, then up_putc will not work.  In fact,
> >> any calls to up_putc() could hang.  If the serial console is the syslog
> >> debug channel, then up_putc is called from syslog under certain
> conditions:
> >>
> >>    * Syslog output from an interrupt handler
> >>    * Syslog() is called with LOG_EMERG
> >>    * Syslog() is called early in the initialization (while using the
> >>      g_default_channel)
> >>
> >> up_putc is also used in most very low level startup logic in the
> >> PROGRESS macro that outputs the ABCDEF that you see when booting most
> >> NuttX systems.
> >>
> >> What happens if the serial device used by up_putc is not initialized?
> >> It will certainly fail to ouput anything but could also hang on a busy
> >> wait polling an uninitialized device.
> >>
> >>
> >>
>
>

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