According to the description of pthread_mutex_lock() (in the function's comment block):
"If a signal is delivered to a thread waiting for a mutex, upon return from the signal handler the thread resumes waiting for the mutex as if it was not interrupted." But I don't see it. From my reading of the code (please correct me if I'm mistaken): pthread_mutex_lock() is a thin wrapper around pthread_mutex_timedlock() with NULL abs_timeout. The comment block above pthread_mutex_timedlock() does not make a similar statement regarding receipt of a signal. pthread_mutex_timedlock() calls pthread_mutex_take() with a intr value of true, which in turn calls pthread_sem_take() with intr value of true, which calls nxsem_wait(). nxsem_wait() returns -EINTR if awakened by a signal. In the above mentioned callers, I don't see any logic that detects this case and resumes waiting for the mutex as if it was not interrupted. Am I correct? Thanks, Nathan
