Hi Maxim, why do you think that data size can be divided to cipher block size with 0 remainder.
I used to think that page size 4096 is always divisible by a usual block cipher block size, e.g 32, 16 or 8 bytes чт, 31 янв. 2019 г. в 13:11, Максим Степачёв <maksim.stepac...@gmail.com>: > Hi, I have been trying to solve a problem with calculation size for > encryption mode, it's ticket IGNITE-11129. But I found an additional place > for wrong behavior. I'm confused, Is it fine or wrong? Look at > *KeystoreEncryptionSpi#encryptedSize*, the result calculation works as > > (dataSize / BLOCK_SZ + cntBlocks) * BLOCK_SZ; > > But we don't have a guarantee that dataSize is multiple of BLOCK_SZ. > Should we use this code: > > ((dataSize + BLOCK_SZ - 1) / BLOCK_SZ + cntBlocks) * BLOCK_SZ; > > If yes, I'll fix it. >
