On Wed, 20 Mar 2024 14:33:35 -0700
Tyler Retzlaff <roret...@linux.microsoft.com> wrote:
> +#ifdef RTE_TOOLCHAIN_MSVC
> +#define __rte_constant(e) 0
> +#else
> +#define __rte_constant(e) __extension__(__builtin_constant_p(e))
> +#endif
> +
I did some looking around and some other project have macros
for expressing constant expression vs constant.
Implementing this with some form of sizeof math is possible.
For example in linux/compiler.h
/*
* This returns a constant expression while determining if an argument is
* a constant expression, most importantly without evaluating the argument.
* Glory to Martin Uecker <martin.uec...@med.uni-goettingen.de>
*
* Details:
* - sizeof() return an integer constant expression, and does not evaluate
* the value of its operand; it only examines the type of its operand.
* - The results of comparing two integer constant expressions is also
* an integer constant expression.
* - The first literal "8" isn't important. It could be any literal value.
* - The second literal "8" is to avoid warnings about unaligned pointers;
* this could otherwise just be "1".
* - (long)(x) is used to avoid warnings about 64-bit types on 32-bit
* architectures.
* - The C Standard defines "null pointer constant", "(void *)0", as
* distinct from other void pointers.
* - If (x) is an integer constant expression, then the "* 0l" resolves
* it into an integer constant expression of value 0. Since it is cast to
* "void *", this makes the second operand a null pointer constant.
* - If (x) is not an integer constant expression, then the second operand
* resolves to a void pointer (but not a null pointer constant: the value
* is not an integer constant 0).
* - The conditional operator's third operand, "(int *)8", is an object
* pointer (to type "int").
* - The behavior (including the return type) of the conditional operator
* ("operand1 ? operand2 : operand3") depends on the kind of expressions
* given for the second and third operands. This is the central mechanism
* of the macro:
* - When one operand is a null pointer constant (i.e. when x is an integer
* constant expression) and the other is an object pointer (i.e. our
* third operand), the conditional operator returns the type of the
* object pointer operand (i.e. "int *). Here, within the sizeof(), we
* would then get:
* sizeof(*((int *)(...)) == sizeof(int) == 4
* - When one operand is a void pointer (i.e. when x is not an integer
* constant expression) and the other is an object pointer (i.e. our
* third operand), the conditional operator returns a "void *" type.
* Here, within the sizeof(), we would then get:
* sizeof(*((void *)(...)) == sizeof(void) == 1
* - The equality comparison to "sizeof(int)" therefore depends on (x):
* sizeof(int) == sizeof(int) (x) was a constant expression
* sizeof(int) != sizeof(void) (x) was not a constant expression
*/
#define __is_constexpr(x) \
(sizeof(int) == sizeof(*(8 ? ((void *)((long)(x) * 0l)) : (int *)8)))
