On Mon, 2021-09-06 at 15:00 +0800, Qiming Chen wrote: > The RTE_ALIGN macro is aligned upwards. If the buf_size variable is not > aligned with 1 << I40E_RXQ_CTX_DBUFF_SHIFT, the rx_buf_len is larger than > the actual mbuf memory after the operation. When receiving the packet, if > the packet is larger than the configured buf_size, it will cause a memory > stepping event. > > The patch uses the RTE_ALIGN_FLOOR down alignment macro to correct the > problem. > > Fixes: c1715402df8f ("i40evf: fix jumbo frame support") > Cc: sta...@dpdk.org > > Signed-off-by: Qiming Chen <chenqiming_hua...@163.com> > --- > drivers/net/i40e/i40e_ethdev_vf.c | 2 +- > 1 file changed, 1 insertion(+), 1 deletion(-) > > diff --git a/drivers/net/i40e/i40e_ethdev_vf.c > b/drivers/net/i40e/i40e_ethdev_vf.c > index 924da8dfb4..5b1c8e76ab 100644 > --- a/drivers/net/i40e/i40e_ethdev_vf.c > +++ b/drivers/net/i40e/i40e_ethdev_vf.c > @@ -1927,7 +1927,7 @@ i40evf_rxq_init(struct rte_eth_dev *dev, struct > i40e_rx_queue *rxq) > RTE_PKTMBUF_HEADROOM); > rxq->hs_mode = i40e_header_split_none; > rxq->rx_hdr_len = 0; > - rxq->rx_buf_len = RTE_ALIGN(buf_size, (1 << I40E_RXQ_CTX_DBUFF_SHIFT)); > + rxq->rx_buf_len = RTE_ALIGN_FLOOR(buf_size, (1 << > I40E_RXQ_CTX_DBUFF_SHIFT)); > len = rxq->rx_buf_len * I40E_MAX_CHAINED_RX_BUFFERS; > rxq->max_pkt_len = RTE_MIN(len, > dev_data->dev_conf.rxmode.max_rx_pkt_len);
Added to 20.11.4 pipeline, thanks!