On Mon, 2021-09-06 at 15:00 +0800, Qiming Chen wrote:
> The RTE_ALIGN macro is aligned upwards. If the buf_size variable is not
> aligned with 1 << I40E_RXQ_CTX_DBUFF_SHIFT, the rx_buf_len is larger than
> the actual mbuf memory after the operation. When receiving the packet, if
> the packet is larger than the configured buf_size, it will cause a memory
> stepping event.
> 
> The patch uses the RTE_ALIGN_FLOOR down alignment macro to correct the
> problem.
> 
> Fixes: c1715402df8f ("i40evf: fix jumbo frame support")
> Cc: sta...@dpdk.org
> 
> Signed-off-by: Qiming Chen <chenqiming_hua...@163.com>
> ---
>  drivers/net/i40e/i40e_ethdev_vf.c | 2 +-
>  1 file changed, 1 insertion(+), 1 deletion(-)
> 
> diff --git a/drivers/net/i40e/i40e_ethdev_vf.c 
> b/drivers/net/i40e/i40e_ethdev_vf.c
> index 924da8dfb4..5b1c8e76ab 100644
> --- a/drivers/net/i40e/i40e_ethdev_vf.c
> +++ b/drivers/net/i40e/i40e_ethdev_vf.c
> @@ -1927,7 +1927,7 @@ i40evf_rxq_init(struct rte_eth_dev *dev, struct 
> i40e_rx_queue *rxq)
>                                       RTE_PKTMBUF_HEADROOM);
>       rxq->hs_mode = i40e_header_split_none;
>       rxq->rx_hdr_len = 0;
> -     rxq->rx_buf_len = RTE_ALIGN(buf_size, (1 << I40E_RXQ_CTX_DBUFF_SHIFT));
> +     rxq->rx_buf_len = RTE_ALIGN_FLOOR(buf_size, (1 << 
> I40E_RXQ_CTX_DBUFF_SHIFT));
>       len = rxq->rx_buf_len * I40E_MAX_CHAINED_RX_BUFFERS;
>       rxq->max_pkt_len = RTE_MIN(len,
>               dev_data->dev_conf.rxmode.max_rx_pkt_len);

Added to 20.11.4 pipeline, thanks!

Reply via email to