Hi. I'd wish to make it clear that I referred to this statement:
> > > The Javadoc for FastMath says that it is a replacement for > > StrictMath, > > > which is why I tested against that. An my understanding was: > > Unless I'm missing something, this is a doc mistake then. So we have: [Please correct me if the following statement is wrong.] "StrictMath" must reproduce the _same_ results on any JVM. Then, to be replacement, "FastMath" must reproduce those _same_ (i.e. same as "StricMath") results. Is that the case? If "FastMath" is as fast (or faster), for all methods, than "Math" (while being as accurate), then it is a replacement of "Math". Is that the case? [Luc already answered "Yes" to that question.] Regards, Gilles --------------------------------------------------------------------- To unsubscribe, e-mail: [email protected] For additional commands, e-mail: [email protected]
