No. Indeed not. And if it calls floor then it isn't likely to give the
desired -0 result.
How important is it to return -0 instead of +0 anyway?
On Wed, Jan 19, 2011 at 10:17 AM, sebb <seb...@gmail.com> wrote:
> On 19 January 2011 16:25, Ted Dunning <ted.dunn...@gmail.com> wrote:
> > Slightly slower,
>
> Unfortunately, I suspect it is about twice as slow for this case,
> because FastMath.ceil() actually calls FastMath.floor().
>
> Not ideal for FastMath !
>
> >
> > double y = floor(x):
> > double d = x - y;
> > if (d > 0.5) {
> > return ceil(x);
> > } else {
> > return y;
> > }
> >
> > but it gives your desired result with little (visible) special casing.
> >
> > On Wed, Jan 19, 2011 at 8:04 AM, sebb <seb...@gmail.com> wrote:
> >
> >> FastMath.rint(x) has the following code:
> >>
> >> double y = floor(x);
> >> double d = x - y;
> >>
> >> if (d > 0.5) {
> >> return y+1.0; // round up
> >> }
> >> ...
> >>
> >> For -0.5 < x < 0 the rounding up generates +0.0 - rather than -0.0,
> >> as expected by the sign of the input parameter.
> >>
> >> Is there an easy way to fix this, other than explicitly checking for y
> ==
> >> -1.0?
> >>
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> >
>
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