I do not think so, from LinkedList implementation:

    /**
     * Return the indexed entry.
     */
    private Entry entry(int index) {
        if (index < 0 || index >= size)
            throw new IndexOutOfBoundsException("Index: "+index+
                                                ", Size: "+size);
        Entry e = header;
        if (index < size/2) {
            for (int i = 0; i <= index; i++)
                e = e.next;
        } else {
            for (int i = size; i > index; i--)
                e = e.previous;
        }
        return e;
    }

It will iterate on every call.

Enough of this, as I think it is becoming a little out of subject for
the ANT list :-)

Jose Alberto

> -----Original Message-----
> From: Kev Jackson [mailto:[EMAIL PROTECTED] 
> Sent: 28 February 2005 11:19
> To: Ant Developers List
> Subject: Re: Massively OT, 'Closures in Java' [was Re: AW: 
> [Patch] modifiedselector, style, remove unused code, slightly 
> more lazy DigestAlgorithm.getValue (now with added source code -doh!)]
> 
> 
> Jose Alberto Fernandez wrote:
> 
> >AFAIU, LinkedList.get(N) requires traversing the list to 
> position N on 
> >every call [O(n^2)], so usage of an iteratoe is much cheaper on this 
> >case as there is no array behind the scenes.
> >
> >Jose Alberto
> >  
> >
> I've just worked out why it's ok to do it this way (with 
> respect to my 
> particular use-case).  Basically I *want* to traverse the 
> entire list, 
> I'm not trying to pick out any particular position in the list (yes 
> truly expensive using LinkedList.get(i)).  In my method I simply call 
> get(i) from 0..List.size():
> 
> from docs
> <quote>Operations that index into the list will traverse the 
> list from 
> the begining or the end, whichever is closer to the specified 
> index.</quote>
> 
> So as I'm asking for position 0, the traversal starts at the 
> head of the 
> list, then I simply walk the list with the loop calling get(i), which 
> also happens to be the next element in the list from where the list 
> cursor currently is (ListIterator interface docs).  Serendipity I 
> suppose, but my usage is the most efficient for LinkedLists and also 
> happens to be performant with ArrayLists, to do the 
> particular traversal 
> that I'm doing.
> 
> Kev
> 
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