On Wed, May 21, 2003 at 09:53:33AM -0700, John H. Robinson, IV wrote: > let's see if we can make the per-item quorum behave like the per-vote > quorum where a vote _against_ an item causes that item to win:
> quorum of R=12. two options, plus the default option. a single voter. > 1 BA > A.6.2. If the ballot has a quorum requirement R any options other than > the default option which do not receive at least R votes ranking > that option above the default option are dropped from > consideration. > B and A each have only one vote over D, thus B and A are both dropped > from consideration. that leaves one vote for D. > there is no majority ratio, so A.6.3 does not apply. A.6.4 has only D, > so D would win. > thus, in the case of a single voter AGAINST the default option, the > default option wins. this is not very likely, but this is also the case. Why do you believe it's meaningful to distinguish between "the default option wins" and "the entire vote is thrown out"? When is status quo != the default option? -- Steve Langasek postmodern programmer
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