On Sun, Nov 17, 2002 at 07:27:28PM +0100, Jochen Voss wrote: > .SUM A: 0 27 24 29 29 > .SUM B: 22 0 25 29 28 > .SUM C: 25 24 0 30 32 > .SUM D: 21 21 19 0 30 > .SUM X: 21 22 18 18 0 > into it, to get > .TIE A > .TIE C
Hmm.. I think you're right. A doesn't directly defeat C -- it only transitively defeats C through B, and while C does defeat A, B defeats C at the same strength. So there's no reason to consider the B's defeat of C as having any more or less importance than C's defeat of A. I retract my statement that an option with no propositions doesn't belong in the Schwartz set. Instead: an option can't be eliminated from the schwartz set after all propositions involving that option have been eliminated. But I need to think a bit more about how I define ties. Thanks, -- Raul
