Hi, Anthony Towns: > > > v. If this new Schwartz set contains only one option, that > > > option wins. > > > > > As per the definition, there is no such thing as a one-option Schwartz > > set
> Uh, if C is the Condorcet winner, or becomes the Condorcet winner after > ignoring some defeats of it, the Schwartz set has only one option. Actually you're right, the definition allows that. I was thinking not of the definition but of the list of steps we're going through, and we're using the "if there's a clear winner, then we're done, else build a Schwartz set" method, as opposed to the equivalent "build a Schwartz set, and if that has only one member, that's the winner" procedure. -- Matthias Urlichs | noris network AG | http://smurf.noris.de/
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