On Wed, Nov 13, 2002 at 06:13:14PM -0500, Buddha Buck wrote:
> The Schultz Set = { A | A>>>A }
> Note: Because A==A, it isn't the case that A>>A,
This is clever, but wrong. Consider an election with people voting:
30 x ABCD
40 x ACDB
50 x ADBC
A wins unanimously and is the only member of the *Schwartz* set. However,
B beats C beats D beats B, so { x | x >>> x } = {B, C, D}.
Alternately, consider something like:
40 x AB CDE
30 x AB DEC
20 x BA DEC
50 x BA ECD
A and B are equal (70 votes each), and C > D > E > C, but A,B both beat
each of C,D,E, but { x | x >>> x } = {A,B,C,D,E}.
The correct restatement is something more like:
{ x | forall y: y >> x --> x >>> y }
Cheers,
aj
--
Anthony Towns <[EMAIL PROTECTED]> <http://azure.humbug.org.au/~aj/>
I don't speak for anyone save myself. GPG signed mail preferred.
``If you don't do it now, you'll be one year older when you do.''
pgptaGmNv7A3V.pgp
Description: PGP signature
