Raul Miller:
> >        iv. If eliminating the weakest propositions would not eliminate
> >            all votes, a new Schwartz set is found based on the newly
> >            revised set of propositions.

On Sat, Nov 16, 2002 at 05:23:13AM +0100, Matthias Urlichs wrote:
> Note that ALL propositions are considered here, not just those
> participating in the Schwartz set.

Hmm.. that's not what I was trying to say.  Thanks.

> >        v. If this new Schwartz set contains only one option, that
> >           option wins.
> > 
> As per the definition, there is no such thing as a one-option Schwartz
> set, so actually you'll have to restart with step 5. You might therefore
> replace the last two sections with a simple

Hmm... I think Isee what you mean.  Thanks again.

-- 
Raul


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