* 2023-12-17 10:58:28+0000, Andy Smith wrote: > On Sun, Dec 17, 2023 at 10:12:11AM +0000, Albretch Mueller wrote: >> you get seconds in dt00 and dt02 and then the difference. You can't >> go: $(( dt02 - dt00 )) because bash Arithmetic is 10-based. > > Why don't you just get the time as epoch time e.g. "date +%s" and > then you can subtract one from the otherĀ¹.
Also, Bash has variable EPOCHSECONDS which expands to the current Unix epoch time. $ echo $EPOCHSECONDS; sleep 5; echo $EPOCHSECONDS 1702812641 1702812646 -- /// Teemu Likonen - .-.. https://www.iki.fi/tlikonen/ // OpenPGP: 6965F03973F0D4CA22B9410F0F2CAE0E07608462
signature.asc
Description: PGP signature