On 5/29/22 9:44 AM, David Wright wrote:
On Sun 29 May 2022 at 15:02:35 (+0200), Jörg-Volker Peetz wrote:
Jim Popovitch wrote on 28/05/2022 21:40:
Not exactly Debian specific, but hoping that someone here can help.
I have a file of regex patterns and I use grep like so:
~$ grep -f patterns.txt /var/log/syslog
What I'd like to get is a listing of all lines, specifically the line
numbers of the regexps in patterns.txt, that match entries in
/var/log/syslog. Is there a way to do this?
How about this:
$ grep -of patterns.txt /var/log/syslog.1 | grep -n -f - patterns.txt
That will only work for literal patterns, not regex ones.
Cheers,
David.
I may be missing a lot but I will risk throwing in my 2 cents (which is
no longer worth the proverbial amount with
the current inflation)
$cat -n /var/log/syslog | grep warn
and it found "warn" in the syslog file and provided line numbers. I have
not used the -f option
(but am now aware of it in the pastfrom your post -- thank you. Might
file that away for future use but will not press
my luck at the moment).
My approach saves me the effort of writing a scriptl. Ahh, the Perl
philosophy of "there is more than one way to do it".
