On 2018-12-19 09:12, mick crane wrote:
On 2018-12-19 08:34, deloptes wrote:
mick crane wrote:
yes but there is only one 100, only one key can have it.
I still try to figure out what goes on with the hash pairs
with a longer list of numbers your example seems to pick up on the
values somehow.
I dunno, unless there is something about using $_ in a loop being
unreliable ?
I persevere to succeed
(1=>8,2=>20,6=>100,15=>100....)
this is what you originally posted, so both 6 and 15 match 100 from
the list
when key is 6 it compares 100 with each element from the list and
matches
100. Same goes for 15.
No idea what you mean!
regards
given a set of *unique* numbers ( there is just one of the numbers in
the list)
and a list of possible pairings find which pairs you can make from the
list.
6 can pair with 100 and 15 can pair with 100 but they cannot both be
in the list of possible pairings because there is only one 100.
just to be a bit clearer.
given a list A of *unique* numbers
and a list B of possible pairings find which pairs you can make from the
list A.
6 can pair with 100 and 15 can pair with 100 but they cannot both be
in the list of possible pairings because there is only one 100.
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Key ID 4BFEBB31
