-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Sun, Jan 14, 2018 at 03:46:06PM +0300, Gokan Atmaca wrote: > Hello > > I have the user list and the password list. I shot them with BASH. I > want to give passwords to the usernames in these separate files in > order. > > File names: > Users.list > Passwords.list > > In a loop, I have to not throw them into users of these passwords. I > did this for it, but it did not work. > > #!bin/bash > passwords = $ (cat passwords.list) > for i in $ (cat passwordlist); do my program $ i $passwords; done
Too little context; what exactly doesn't work? I'd suggest going in little chunks. First try: for i in $(cat passwords.list) ; do echo "<$i>" ; done Does that do what you want? Unrelated question: why are you doing in your first line passwords=$(cat passwords.list) when in the second line you're doing $(cat passwordlist) anyway? And shouldn't the second line be $(cat passwords.list? (NOTE: to assign a shell variable, *no* space before the '='; this won't work: the shell will read first 'passwords' then <space> and try to interpret passwords as a command; but this first line seems superfluous anyway). > How do I make an Array? Or how can I solve it? I don't think you need an array for what you are trying. But it would make sense to get the shell basics straight, first. Come back with more questions! Cheers - -- tomás -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.12 (GNU/Linux) iEYEARECAAYFAlpbY1cACgkQBcgs9XrR2kbYKACfZp0o9RthqaaibDo3Agva/UVz 47gAnjnzfrc7U8m5oUIKqtf6Hd9EufCd =M0N3 -----END PGP SIGNATURE-----
