Denis Witt <denis.w...@concepts-and-training.de> wrote:
> I've a problem with a script. It's a wrapper for a program which uses
> for example '*' as a parameter. It could also be 'foobar*' [...]
Do you expect the program to see the asterisk character itself, or an
expansion into the corresponding list of files in the current folder?
#!/bin/sh
read X; echo "X=> $X <"
If you enter a single asterisk ('*'), that's what X will be set to.
#!/bin/sh
echo "*=> $* <"
If you supply an asterisk on the command line, the shell (not your
program) will expand that to match files in the current folder.
So if you're expecting your dialog --inputbox to accept a single
character asterisk ('*') or a shell pattern such as foobar* then that's
what it will pass to your program. It won't match against the files in
the current folder because that's not a function of the dialog program -
it's a function of the shell.
Apologies if this is blindingly obvious.
You either need to eval the value returned from dialog --inputbox or
else ensure that you DO NOT quote it when you use it as a command line.
> The parameter is set correctly: "echo ${parameter}" gave me exactly what
> I expect to see ('*')
Ah. Not necessarily. You've not quoted the variable, so it's liable for
filename matching. But if the shell cannot expand the pattern then it
leaves the pattern alone. See this example:
mkdir /tmp/t && cd /tmp/t
touch a1 a2 b1 b2
X='a*'
echo $X
X='d*'
echo $X
mkdir x && cd x
X='*'
echo $X
touch a b c
echo $X
> Unfortunately when the parameter is passed to the
> program it looks like this (according to "set +x"):
> /usr/bin/salt ''\''*'\''' state.highstate -v test=True -b 10
> How can I avoid that?
This should work (notice the lack of quotes around the variable),
assuming the script is running in the folder that the user expects:
/usr/bin/salt $parameter state.highstate -v test=True -b 10
Chris
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