On Fri, Dec 16, 2011 at 1:11 AM, Bob Proulx <b...@proulx.com> wrote: > lina wrote: >> aaa >> model 0 >> bbb >> ddd >> model 1 >> ccc >> >> I want to print out the parts which match the "model 0" and ends with >> match "model 1" >> >> for the final expected output is: >> >> model 0 >> bbb >> ddd > > Try this: > > sed -n '/^model 1/q;/^model 0/,$p'
Just realize the sed -n '/model 0/,/model 1/'p can also do that. (so newbie I was/am). just still don't understand above sentence. sed -n '/^model 1/q;/^model 0/,$p' Thanks, > > Bob -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: http://lists.debian.org/cag9cjmk8nau2cjow+3q-0he9sqmm8-jbmxjylodezoyaunq...@mail.gmail.com
