On Fri, Sep 16, 2011 at 12:47:11AM +0800, lina wrote:
> > > You have options.
> > Just some additional remarks:
> > a) the for-loop won't work, as "FILE" is expanded to the name including
> > the .txt, so if you have a file "a.txt" this loop will execute
> > mv a.txt.txt a.txt.pdf
> > You need instead
> > for FILE in *.txt; do mv $FILE `basename $FILE .txt`.pdf; done
> > in order to remove the ".txt" from the variable "$FILE"
> >
>
> Seriously, I have problem testing this one,
>
> the come out is like:
>
> (basename $FILE .txt.pdf
>
> sorry I might be so sleepy, I will check another time,
You probably typed a mixture with the solution from Aaron :-)
I think the opening parenthesis "(" CAN'T stem from my line -- there
should be no "("
In fact, I use just a different syntax then Aaron to achieve the same
result: We want to evaluate the command "basename $FILE .txt" and pass
the output of this command as argument to mv (this feature is called
"command substitution" in the man-page).
Now, there are two ways to achieve this in bash:
1) use $(...)
2) use `...`
There are only some minor difference how a backslash is treated within
$(...) and `...`.
Axel
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