On Sat, Mar 19, 2011 at 10:02:24PM -0400, Jim Green wrote: > this is what I have from fdisk -l, I have lvm on /dev/md1, md1 is a > raid10 array with 4x2T drives. > Disk /dev/md1: 4000.5 GB, 4000525058048 bytes > 2 heads, 4 sectors/track, 976690688 cylinders > Units = cylinders of 8 * 512 = 4096 bytes > Sector size (logical/physical): 512 bytes / 512 bytes > I/O size (minimum/optimal): 524288 bytes / 2097152 bytes > Disk identifier: 0x00000000
Note that 4000525058048 != 4 x 2^40 (4398046511104) > this is what I have from pvdisplay > --- Physical volume --- > PV Name /dev/md1 > VG Name 2600k > PV Size 3.64 TiB / not usable 0 > Allocatable yes > PE Size 4.00 MiB > Total PE 953799 > Free PE 831052 > Allocated PE 122747 > PV UUID WUpkTR-xyCK-HGOc-Hk7Q-OfBp-Mqsz-GubCy7 2^40 = 1099511627776 4000525058048 / 1099511627776 = 3.6384563446044921875 ~= 3.64 > I don't know why I only have a 3.64T pv size, it should be 4T I think, > in the installation of lenny i use ext3 for all the partitions, > also I set the unused space for each partition as 1%. > > Thank you if you have an explanation or if you have ways to reclaim > the 0.36 T from my arrays. The difference is between what vendors use to describe their drives (TB, meaning trillions of bytes) and what sane computer systems use (TiB, meaning 2^40 bytes). > Jim --Greg -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: http://lists.debian.org/20110320021554.ga29...@anthropohedron.net
