Short answer:

It's not possible.

Long answer:

After the research it took me, I'm just too damned lazy to write it up.  Just 
trust me, can't be done.



Hal

On Feb 24, 2011, at 3:49 AM, Hal Vaughan wrote:

> I'm using a small program that's started by xinetd.  The incoming signal to 
> it would be a broadcast signal, which means it has to be UDP.
> 
> I wrote two versions of the test program, one in Perl and one as a bash 
> script and both ran into the same problem.
> 
> They worked fine when I first set them up and set up the service in xinetd as 
> using TCP.  Then I changed the service to UDP and made the appropriate 
> changes to my programs.
> 
> They still logged everything, they still received incoming messages from the 
> other test programs that were communicating to them (either directly or 
> through a broadcast), but they did NOT send any data back.  I checked it this 
> with Wireshark.  The incoming data showed up, but the data these programs 
> were supposed to send back didn't even go out over the LAN.
> 
> The programs ran and exited properly, but the output to the network never 
> showed up.
> 
> While I don't know but so much about networking, I know TCP and UDP sockets 
> are notably different.  I can't find anything in the documentation that 
> indicates that for a program using UDP sockets, that it has to use something 
> other than STDIN and STDOUT.  I even found sources that say you SHOULD still 
> be using STDIN and STDOUT for programs using UDP through xinetd.
> 
> I don't consider this just a programming question, since it's the same in 
> both languages.  I strongly suspect there's a different way to handle the 
> output that's supposed to go back over the network for UDP (vs. TCP).
> 
> Any ideas on what might be needed?
> 
> 
> Thank you!
> 
> 
> Hal
> 
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