On Thu, 27 Jan 2011 12:06:39 -0200 Eduardo M KALINOWSKI <edua...@kalinowski.com.br> wrote:
> On Qui, 27 Jan 2011, Celejar wrote: > >> Now another question, which nobody seems to have noticed/mentioned. > >> > >> Since CBC encryption is a "recursive algorithm, the encryption of the n-th > >> block requires the encryption of all preceding blocks, 0 till n-1." [1] > >> Now, does it mean if my HD has a bad block in the middle, then all the > >> remaining data will be gone entirely? > >> > >> 1. http://clemens.endorphin.org/LinuxHDEncSettings > > > > This seems correct - Wikipedia also says that with CBC: > > > > "Note that a one-bit change in a plaintext affects all following > > ciphertext blocks." > > > > http://en.wikipedia.org/wiki/Block_cipher_modes_of_operation#Cipher-block_chaining_.28CBC.29 > > That is correct, but the whole disk is not one single CBC-encoded > unity. The link in the question message says that: > > [...] CBC chaining is cut every sector and restarted with a new > initialisation vector (IV), so we can encrypt sectors individually. > The choice of the sector as smallest unit matches with the smallest > unit of hard disks, where a sector is also atomic in terms of access. > > http://clemens.endorphin.org/LinuxHDEncSettings Ah, ok. Thanks. Celejar -- foffl.sourceforge.net - Feeds OFFLine, an offline RSS/Atom aggregator mailmin.sourceforge.net - remote access via secure (OpenPGP) email ssuds.sourceforge.net - A Simple Sudoku Solver and Generator -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: http://lists.debian.org/20110127092054.1c13c435.cele...@gmail.com
