Hello,
> Andrew Sackville-West skrev:
> > On Tue, Oct 13, 2009 at 06:46:31PM -0400, Chris Jones wrote:
> >
> >> On Tue, Oct 13, 2009 at 03:35:19PM EDT, Håkon Alstadheim wrote:
> >>
> >>> Israel Garcia skrev:
> >>>
> >>>> Hi List,
> >>>>
> >>>> It's a simple question but difficult to me :-).
> >>>>
> >>>> How can I delete all files on a folder /xxxx but keeping only the
> two
> >>>> latest (newest) files?
> >>>>
> >>>>
> >>>>
> >>> untested, run it with 'echo' in front first to test:
> >>> rm $(ls -rt | sed '1,2d')
> >>>
> >> sed rocks...!
> >>
> >
> >
> > indeed. wow.
> >
> > A
> >
> Due to all the positive feed-back, I actually tested the "ls -rt"-bit,
> and sure enough, the 'r' makes ls list the newest files _last_, so you
> DON'T want 'r'. This makes the correct command:
>
> rm $(ls -t | sed '1,2d')
>
>
> You should _still_ test it first using 'echo ', to make sure there are no
> subdirectories in there, and on general principles. Adapt to whatever you
> have in the directory.
>
>
Using the find command ensures that directories are skipped. The -maxdepth
0 restricts the search to the current directory:
rm $(find . -maxdepth 0 -type f | xargs ls -t| sed 1,2d)
However, this does not work, if you have files with spaces! Then the best
is to use the -print0 and xargs -0 that uses zero-delimited strings instead
of space delited strings. Also the rm must be run in a loop and with
quotation marks around the filename:
find . -maxdepth 0 -type f -print0 | xargs -0 ls -t| sed 1,2d |
while read f; do rm -f "$f" ; done
BR,
Roland
>
>
>
>
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