Hi,
I didn't test that script, just writing it from memory, but maybe that gives
you some ideas:
#!/bin/bash
prog1 &
prog2 &
while [ $(ps -A | grep -E 'prog1|prog2') == "0" ]
do
sleep 5
done
prog3
more or less like that
greetings,
vitaminx
2009/6/23 Kamaraju S Kusumanchi <raju.mailingli...@gmail.com>
> I have three programs - say proga, progb, progc.
>
> proga, progb are completely independent. They take couple of hours to
> finish. The time to complete proga, progb are not same.
>
> progc should to be launched only after both proga, progb are finished.
> progc
> takes another couple of hours to finish.
>
> What is good way to automate this problem (that is no manual interaction)?
> I
> prefer to use nohup since sometimes I have to log out of the machine before
> the whole process finishes.
>
> Currently I have a shell script that works as below.
> 1) launch proga, progb in the background using nohup.
> 2) Ask proga, progb to write a file when they finish.
> 3) Every five minutes check if these files are present. If they are
> present,
> launch progc.
>
> This gets me going for now. But it looks terribly inefficient. I would
> appreciate if someone can provide a better solution.
>
> Using Debian Lenny (Stable).
>
> thanks
> raju
> --
> Kamaraju S Kusumanchi
> http://malayamaarutham.blogspot.com/
>
>
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