On Wed, Mar 04, 2009 at 16:24:27 -0500, kamaraju kusumanchi wrote: [...]
> Now, > I would like to replace all the occurrences of > > a(ijk)1b with a(ijk)23b > a(jik)1b with a(jik)23b > a(ikj)1b with a(ikj)23b > and so on for all the strings such as a(???) > > Because of the size of the files involved, the number of files on > which I have to perform this operation I decided to use sed (instead > of doing it manually in vim) [...] > Is there any way > to write something like > > s/a(???)1b/a(???)23b/g > > where the second ??? is the string matched by the first regular > expression. sed -e 's/a(\(...\))1b/a(\1)23b/g' -- Regards, | http://users.icfo.es/Florian.Kulzer Florian | -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org
