On Sunday 2008 December 21 01:02:04 M.Lewis wrote: > Boyd Stephen Smith Jr. wrote: > > On Saturday 2008 December 20 22:42:10 M.Lewis wrote: > >> The filesystem size (according to the superblock) is 244190000 blocks > > > > ^^^^^^^^^ > > > >> The physical size of the device is 244189984 blocks > > > > ^^^^^^^^^ > > > > 244190000 > 244189984. You need to resize your filesystem to actually > > fit on /dev/md0. > > Disk /dev/sda: 1000.2 GB, 1000204886016 bytes > Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes > > I'm confused. It's complaining about bad partition or superblock. You > said I need to resize my fs, but according to fdisk, they are the same. > Aren't they?
Your filesystem isn't on raw partitions. It is on the /dev/md0 device. That device is 244189984 blocks, as e2fsck told you. You could also use blockdev --getsize64 to get the size of the device in bytes. The "bad partition" part of the message is a bit misleading, it means "bad block device" but was written with the assumption that the block device the filesystem is on is a partition and not something else. In your case it is a software RAID device. The "bad ... superblock" it is talking about is the ext2/3 superblock that contains the filesystem information. The block device (/dev/md0) and the ext2/3 superblock (stored multiple times on /dev/md0) disagree on the size of the filesystem. The boot process (IIRC, mount in specific) correctly assumes that one of them must be wrong and thus "bad". I assume that /dev/md0 knows it's size, so the filesystem superblock is bad and you should correct it by resizing the filesystem. > Are you talking about LVM sizing? I'm not sure what you mean by "LVM sizing". I am talking about the size of the device you've put the filesystem on, and it really doesn't matter if it's on a LV or not. BTW, in case you didn't know, modern software RAID uses some space on the component block devices to store a RAID superblock that contains the UUID of array, among other things, by default. This can be turned off, but it would require re-creating the array. This means that a RAID-1 over two devices will be slightly smaller than the smallest device and RAID-0 over two devices will be slightly smaller than twice the smallest device. -- Boyd Stephen Smith Jr. ,= ,-_-. =. b...@iguanasuicide.net ((_/)o o(\_)) ICQ: 514984 YM/AIM: DaTwinkDaddy `-'(. .)`-' http://iguanasuicide.net/ \_/
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