tôba wrote:
> Hello,
>
> Can you help me with a bash command?
> I a directory, I want to extract with a command line for jpg name files.
> I have a lot of:
>
> icon_3620_0_1.jpg
> icon_3616_0_1.jpg
> icon_3563_0_1.jpg
>
> I want to extract the number betwen icon_*_0_1.jpg AND I want to use
> the entire filename too in the same command.
>
> The goal is to create a directory called 3620 and move the
> icon_3620_0_1.jpg file into this directory.
>
> So, I did like this for test:
>
> # for a in `ls | sed -e s'/_/ /g' | awk '{print $2}'`; do echo
> icon_$a_0_1.jpg; done
>
> I hope it should give me:
>
> icon_3620_0_1.jpg
> icon_3616_0_1.jpg
> icon_3563_0_1.jpg
>
> like the original
>
> BUT in my surprise, it shows:
>
> icon_.jpg
> icon_.jpg
> icon_.jpg
> icon_.jpg
>
> Why?
> Where is the $a_0_1 gone? Surely I missed something but I cannot
> find it.
> Can you tell me how to reproduce the exact filename so?
>
> Best regards,
>
> --
> Tôba
>
>
Hello, do you means like that?
for a in `ls | sed -e s'/_/ /g' | awk '{print $2}'`; do echo
icon_${a}_0_1.jpg; done
A better way maybe is:
[EMAIL PROTECTED]:~/test/jpg$ touch icon_3563_0_1.jpg icon_3616_0_1.jpg
icon_3620_0_1.jpg
[EMAIL PROTECTED]:~/test/jpg$ ls
icon_3563_0_1.jpg icon_3616_0_1.jpg icon_3620_0_1.jpg
[EMAIL PROTECTED]:~/test/jpg$ ls | awk -F_ '{print $2}'
3563
3616
3620
[EMAIL PROTECTED]:~/test/jpg$
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