roberto wrote:
hello
i use the "df -h" or "du -h"command to check how much disk space is
occupied by files and directories
but is it possible to sort the output list in an order such that the
first (or conversely the last) item is the largest in size ?
thank you
Unfortunately, df will often produce 2 lines of output for a single
filesystem if the name is too long. Here's a pipeline that
seems to handle that to produce decent output:
df | sed 1q; df | sed -n -e 1d -e '/^ /{H; s/.*//g; x; s/\n//; p; n}; x;
p; ${x; p}' | column -t | sort -n -r -k 2
--
To UNSUBSCRIBE, email to [EMAIL PROTECTED]
with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
