Hello,
Writting a small script to make mozilla show the results of HTML code written in vi, when vi saves, the script automaticly changes mozilla to show that HTML.
I need to know if mozilla is running, if not I need to call it first ... seemed simple
if ! ps ax | grep "mozilla-bin" &>/dev/null; then /usr/local/mozilla/mozilla -P web & .....
This worked the first time then I get
[EMAIL PROTECTED]:/usr/local/myfiles/dave/debian/sh files$ ./HTMLgui 7508 pts/0 S 0:00 grep mozilla-bin
Ie its picking up on the grep process, finding "mozilla-bin", saying yep its running, dont call mozilla & bang, script fails.
Whatever I grep for, grep will find in ps ax as grep xxxxxx, a bit frustrating !!
Help Dave
PS still a newbe BASH scripter, If there is a better way of doing this, let me know.
#!/bin/sh
# HTMLgui ... enable Mozilla to provide a GUI for vi
currentdir=/usr/local/myfiles/dave/websites/current oldhtml="mismatch"
if ! ps ax | grep "mozilla-bin"; then /usr/local/mozilla/mozilla -P web & sleep 3s fi
echo while true; do html=$(ls -t1 $currentdir/*.html | head -n 1) if [ $oldhtml = $html ]; then sleep 1s else echo -e "HTMLgui ... changing to ${html##/*/}" oldhtml=$html /usr/local/mozilla/mozilla -P web -remote "openFile($html)" fi done
Many thanks for all your help, works great now, Dave
PS what is this Galleon thing ?
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