On Fri, 2007-03-09 at 15:01 -0800, L.V.Gandhi wrote:
> I have made a script like this as test1
> #!/bin/bash
> line="3IINFOTECH,20050422000000,118,118,96,98.1,8260440"
> olds=$(echo "$line"|cut -d, -f2)
> echo $olds
> da=${olds:0:8}
> echo $da
> echo "$line" > temp1
> sed -e 's/$olds/$da/' temp1 >>temp
> cat temp1
> cat temp
> When I run get as
> [EMAIL PROTECTED]:~/.qtstalker/data0/export$ test1
> 20050422000000
> 20050422
> 3IINFOTECH,20050422000000,118,118,96, 98.1,8260440
> 3IINFOTECH,20050422000000,118,118,96,98.1,8260440
> I don't find any replacement. Where am I wrong? what should be done to
> get the replacement done?The problem is that you've used single quotes, preventing shell expansion of your variables. Try: sed -e "s/$olds/$da/" temp1 >>temp My guess is that will work for you. -davidc -- gpg-key: http://www.zettazebra.com/files/key.gpg
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