In your example you are saying that $a is the function 'do_chrono', so when you run $a, it runs the function and prints out the result. As another poster indicated, you need to do it slightly differently:
# execute and store result in $a a=$( do_chrono ) # print echo $a Atle - Flying Crocodile Inc, Unix Systems Administrator On Wed, 27 Sep 2006, Hugo Vanwoerkom wrote: > Hi, > > On my way to elapsed time in a bash script, I created the do_chrono > command. It pumps the elapsed time to stdout. > > So if I do: > > a=do_chrono > > and then: > > $a > > I get: 0:3:19. > > Problem: I can't use that $a anywhere, e.g. if I say: > > echo $a > > I would expect to see 0:3:19 again, but I don't, it says > > do_chrono > > > How do I use that $a in command parameters, like logger? > > Thanks! > > H > -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
