2006-04-05 21:16 +0200, Mike McCarty <[EMAIL PROTECTED]>:
> Mitchell Laks wrote:
> > [...]
> > #include <stdio.h>
> > #include <stdlib.h>
> > #include <string.h>
> >
> > typedef struct employee_st {
> > char name[40];
> > int id;
> > } Employee;
> >
> > int main()
> > {
> > int myInt;
> > Employee john;
> >
> > printf("Size of int is %d\n",sizeof(myInt));
>
> This program has defects. The type of the results of
> the sizeof operator is an unsigned integer of unspecified
> size. The only portable way to do this is...
>
> printf("Size of int is %lu\n",(unsigned long)sizeof(int));
The result of sizeof is a size_t, an unsigned type. Couldn't it happen
to be using something bigger than a unsigned long, such as an unsigned
long long? If I have read it correctly, using a C99-compatible
compiler (ISO/IEC 9899:1999) one could simply write
printf("Size of int is %zu\n", sizeof(int));
where z is a length modifier (akin to l o ll) that that specifies a
size_t when printing integers (i.e. with d, u, o, x et al.).
--
Gonzalo HIGUERA DÍAZ <[EMAIL PROTECTED]>
