On Fri, Oct 21, 2005 at 08:45:38PM -0500, Martin McCormick wrote:
> A Bourn shell script I am trying to run isn't behaving like I
> expected it to and I am not sure how to make it play nice. There are
> a bunch of DNS zone files that need the bottom 6 lines chopped off and
> I hoped to do that with a while loop driven by the ls command. In
> order to loose the bottom 6 lines, one must count all the lines,
> subtract 6 from that number and use the new value as a value for head.
> The problem occurs in the way awk is producing output in the loop.
> Here is the script:
>
> #! /bin/sh
> filechop () {
> #This function takes one file at a time and removes the bottom 6 lines.
> #Get a single numerical value stating how many lines are in the file.
> zlength=`wc -l $zonename|awk '{print $1}'`
> shortlength=$(($zlength - 6))
> head -$shortlength $zonename >tmp.zone
> mv tmp.zone $zonename
> return 0
> }
> #main routine
> while zonename=`ls *.zone`;do
> filechop
> done
>
> Things go quite wrong when awk produces a line of output
> instead of one value per line which would drive the rest of the script.
> I have tried putting parentheses around the line reading
>
> zlength=`(wc -l $zonename)|awk '{print $1}'`
>
> And, I have moved the right parenthesis to include the awk call, but
> that changed nothing.
>
> Is there any way to get one value per iteration?
>
> Thanks for any good ideas.
>
> Martin McCormick WB5AGZ Stillwater, OK
> OSU Information Technology Division Network Operations Group
Not sure if I understood the problem correctly, but how about:
#! /bin/sh
filechop () {
#This function takes one file at a time and removes the bottom 6 lines.
#Get a single numerical value stating how many lines are in the file.
zlength=`wc -l $zonename|awk '{print $1}'`
shortlength=$(($zlength - 6))
head -$shortlength $zonename >tmp.zone
mv tmp.zone $zonename
return 0
}
#main routine
for zonename in `ls *.zone`; do
filechop;
done
Simo
--
:r ~/.signature
signature.asc
Description: Digital signature
