Hello list, The following is part of my dmesg output. I have 2 512MB ECC registered ram modules. But only 896MB will be used? What does this mean?
Linux version 2.4.18 ([EMAIL PROTECTED]) (gcc version 2.95.4 (Debian prerelease)) #2 SMP Sun Mar 10 21:28:37 CST 2002 BIOS-provided physical RAM map: BIOS-e820: 0000000000000000 - 000000000009fc00 (usable) BIOS-e820: 000000000009fc00 - 00000000000a0000 (reserved) BIOS-e820: 00000000000e0000 - 0000000000100000 (reserved) BIOS-e820: 0000000000100000 - 0000000040000000 (usable) BIOS-e820: 00000000fec00000 - 00000000fec02000 (reserved) BIOS-e820: 00000000fee00000 - 00000000fee01000 (reserved) BIOS-e820: 00000000fff80000 - 0000000100000000 (reserved) Warning only 896MB will be used. Use a HIGHMEM enabled kernel. found SMP MP-table at 000ff780 hm, page 000ff000 reserved twice. hm, page 00100000 reserved twice. hm, page 000f0000 reserved twice. hm, page 000f1000 reserved twice. On node 0 totalpages: 229376 zone(0): 4096 pages. zone(1): 225280 pages. zone(2): 0 pages. Intel MultiProcessor Specification v1.4 -- Patrick Hsieh <[EMAIL PROTECTED]> GPG public key http://pahud.net/pubkeys/pahudatpahud.gpg -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
