On Wed, May 15, 2002 at 05:17:41PM +0930, Tom Cook wrote: > However, you are not entirely correct. This does, in fact, compile, > with the exception of the type of execve for execv. It also, funnily > enough, doesn't loop infinitely, which makes me think that the execv > call is just failing. I am Interested, but not enough to figure out > Why.
$ gcc -g -Wall -o suidscript suidscript.c suidscript.c: In function `main': suidscript.c:4: warning: passing arg 2 of `execve' from incompatible pointer type suidscript.c:4: too few arguments to function `execve' $ ls suidscript ls: suidscript: No such file or directory Note: I said "semantically", since you pass argv[0] as the command to execute, the program will keep executing itself (if argv[0] is fully qualified). But, if you managed to get it to compile, it no doubt is segfaulting due to noted errors above. -- Eric G. Miller <egm2@jps.net> -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
