on Fri, Apr 27, 2001 at 10:36:57AM -0500, Dave Sherohman ([EMAIL PROTECTED]) wrote: > On Thu, Apr 26, 2001 at 12:32:46PM -0700, Karsten M. Self wrote: > > Another missing specification: does anyone have a good "last weekday of > > month" recipie? > > 'Last weekday of the month' is equivalent to 'Monday - Thursday where > tomorrow is next month or Friday where 3 days from now is next month'. > > So... Set up two cron entries, one for mon-thu, one for fri. > (To additionally optimize, run the mon-thu job only on the 28th-31st of > the month and the fri job on the 26th-31st.) Based off of Rob's solution > to the original question, use test on mon-thu whether `date +%d -d +1day` > == 1 and on fri whether `date +%d -d +3day` < 4. > > That gives us: > > 1 0 28-31 * 1-4 [ "$(date +%d -d +1day)" -eq "1" ] && command -args > 1 0 26-31 * 5 [ "$(date +%d -d +3day)" -lt "4" ] && command -args > > (-lt was used instead of < because it < does an ascii comparison - > "29" < "4". -eq was used instead of == to be consistent; either should > work in that case.)
Also nice. I'm writing this up as a FAQ along the lines of "We should do this more often -- running jobs on nth weekday of the mont and other cron problems". Interestingly, I'd just gone through a similar sort of problem trying to identify last weekday of month using SAS, so the logic is similar. Cheers. -- Karsten M. Self <kmself@ix.netcom.com> http://kmself.home.netcom.com/ What part of "Gestalt" don't you understand? There is no K5 cabal http://gestalt-system.sourceforge.net/ http://www.kuro5hin.org
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