On Tue, Mar 14, 2000 at 01:38:43AM +0200, Shaul Karl wrote: > I guess that the 8 in 10.0.0.0/8 is somehow connected to the subnet mask. > What > is the exact relation? How would I compute the appropriate number for my > network? > Pointers which explain it and/or full explanation will be appreciated.
It's the number of bits in the netmask. 0.0.0.0 0 bits /0 128.0.0.0 1 bit /1 192.0.0.0 2 bits /2 224.0.0.0 3 bits /3 240.0.0.0 4 bits /4 248.0.0.0 5 bits /5 252.0.0.0 6 bits /6 254.0.0.0 7 bits /7 255.0.0.0 8 bits /8 255.128.0.0 9 bits /9 255.192.0.0 10 bits /10 255.224.0.0 11 bits /11 255.240.0.0 12 bits /12 255.248.0.0 13 bits /13 255.252.0.0 14 bits /14 255.254.0.0 15 bits /15 255.255.0.0 16 bits /16 255.255.128.0 17 bits /17 255.255.192.0 18 bits /18 255.255.224.0 19 bits /19 255.255.240.0 20 bits /20 255.255.248.0 21 bits /21 255.255.252.0 22 bits /22 255.255.254.0 23 bits /23 255.255.255.0 24 bits /24 255.255.255.128 25 bits /25 255.255.255.192 26 bits /26 255.255.255.224 27 bits /27 255.255.255.240 28 bits /28 255.255.255.248 29 bits /29 255.255.255.252 30 bits /30 255.255.255.254 31 bits /31 255.255.255.255 32 bits /32 This is sometimes called "CIDR" notation. -- Nathan Norman "Eschew Obfuscation" Network Engineer GPG Key ID 1024D/51F98BB7 http://home.midco.net/~nnorman/ Key fingerprint = C5F4 A147 416C E0BF AB73 8BEF F0C8 255C 51F9 8BB7
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