Quoting Stephen J. Carpenter ([EMAIL PROTECTED]): > The authors concern was that on a big endian system network order and > byte order are the same so hton* and ntoh* do nothing....so how do you > do the swapps... > I suggested a union first (like below) but...whats the "proper" way of > doing it?
The solution is to always run hton before putting stuff on the wire and running ntoh when pulling stuff back. That way you can be sure that the stuff on the wire is always network byte order without having to put in nasty test cases. Mike Stone
