THank for looking into this everyone. Turns out that the sed is not
necessary. The date "+ %a %b %d" statement needs to be modified! I
really need to get my shit together. The correct statement is
date "+%a %b %d" where the space between the + and the %a needs to be
removed.
So the actuall statement could look something like:
grep "$(date "+%a %b %e")" arch.log
I am using the %e instead of the %d to strip the leading "0" from a
day such as ( 01 - 09).
Every one - thank you for your time with my issue. It is very
reasuring to know that when the manual does not have the answers, that
many times our user group does.
______________________________ Reply Separator _________________________________
Subject: Re: HELP: w/ grep on a log file.
Author: jhspies(p)Johann(a)alpha.futurenet.co.za at INTERNET
Date: 6/13/98 4:50 AM
Hallo,
Sorry if this bores you, but I have never used sed before and after
reading this discussion I checked the man page for sed.
What I would like to know is the following:
On Fri, 12 Jun 1998, Steve Mayer wrote:
> Try grep "`date \"+ %a %b %d\" | sed 's/ //'`" arch.log
^ ^
> dave oswald wrote:
> > grep echo \"`date "+ %a %b %d" | sed 's/ //'`\" arch.log
^ ^
What is the meaning of the ` before date and after //'?
What was wrong with dave oswald's effort?
Why wouldn't
grep \"`date "+ %a %b %d" | sed 's/ //'`\" arch.log
work?
Johann
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