Miquel van Smoorenburg wrote:
In article <[EMAIL PROTECTED]>,
Kent West <[EMAIL PROTECTED]> wrote:
A programmer would know this . . , but not me ;-)
I'm using a script to build a file by concatenating portions of two other files. Then end result needs to be checked to make sure a certain word shows up in a line.
I know that "grep programm <this email message>" would return the line:
A programmer would know this . . , but not me ;-)
but what I want returned is just the word "programmer".
sed -ne 's/^.*\(word_here\).*$/\1/p' < file
Here's my test script:
#!/bin/bash
if [ sed -ne 's/^.*\(icewm\).*$/\1/p' < /home.local/snert/.xinitrc ] ; then
echo "Yep"
else
echo "Nope"
fi
and the result:
[EMAIL PROTECTED]:/home.local/snert> ./test.sh ./test.sh: [: sed: integer expression expected Nope
BTW, why not simply
if grep -q word file then # word was present in file bla bla fi
My test script:
#!/bin/bash
if [ `grep -q icewm /home.local/snert/.xinitrc` ] ; then echo "Yep" else echo "Nope" fi
and the result:
[EMAIL PROTECTED]:/home.local/snert> ./test.sh Nope
and if I remove the backtics:
#!/bin/bash
if [ grep -q icewm /home.local/snert/.xinitrc ] ; then echo "Yep" else echo "Nope" fi
which results in:
[EMAIL PROTECTED]:/home.local/snert> ./test.sh ./test.sh: [: too many arguments Nope
and my /home.local/snert/.xinitrc file:
[EMAIL PROTECTED]:/home.local/snert> cat .xinitrc icewm #startkde #gnome #fluxbox
Wow! I never would have thought this to be such a difficult question. But thanks everyone, for the suggestions. I appreciate you trying.
-- Kent
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