On Thu, 25 Apr 2019 10:04:46 +0300 Artem Golubev <agolube...@gmail.com> wrote:
> Hello, I’m using python3.5, python3.7 on Debian 9 stretch
Simply rename the script and delete any socket.pyc file in the same
directory.
* Do not name your script using the name of a module that you will be
importing:
> File "/root/python/projects/test/socket.py", line 7, in <module>
That should be .../test/socket-test.py or socket-script.py
anything except the name of the module you will be importing from
elsewhere.
> This is my code:
The code itself is fine.
>
> ———————-
> import socket
>
> host = 'google.com’
The quotation marks here were mangled by your email client but once
that is fixed, the code works fine.
> port = 80
>
> try:
> sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
> sock.settimeout(0.1)
> result = sock.connect_ex((host, port))
> if result == 0:
> print('Port is UP')
> else:
> print('Port is DOWN')
> except socket.timeout as e:
> print(e)
> ——————————
>
>
> When I execute my code I receive this error
>
> ***************
> Traceback (most recent call last):
> File "/root/python/projects/test/socket.py", line 7, in <module>
> sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
> AttributeError: module 'socket' has no attribute 'AF_INET'
>
> During handling of the above exception, another exception occurred:
>
> Traceback (most recent call last):
> File "socket.py", line 1, in <module>
> import socket
> File "/root/python/projects/test/socket.py", line 14, in <module>
> except socket.timeout as e:
> AttributeError: module 'socket' has no attribute 'timeout'
> ******************
> recently everything worked fine, but some time ago this error
> appeared. And on other OS (Ubuntu, FreeBSD), the code works without
> errors. Please help:) sorry for my English
>
> --
> С уважением,
> Артём
--
Neil Williams
=============
http://www.linux.codehelp.co.uk/
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